bash scripting ..wild card in if statement

Hi everyone I writing a simple bash script and the problem I am having is: I need to search a file with ip addresses and exec a command for each excluding the ip address that ends with .254 which in most cases is the router

for ip in `cat /home/tux/Desktop/file`
do
if [ $ip  = *.254 ];then
echo this is a router
 
done

this is not what my script must do but if this works my script will work

how does your file look like? also describe how you want the output.

ghostdog74 said: how does your file look like? also describe how you want the output.

the file is something like this

10.0.0.1
10.0.0.2
10.0.0.3
10.4.5.12

and it goes on

the output i want is if on of those ips end with 254 i must get a msg "this is a router

# awk -F"." '$NF==254{print $0 " is a router"}' file
10.202.101.254 is a router

*.*.*.254 will match any file of this form ending on 254.

You can also use a case statement

while read ip; do
  case "$ip" in
    *.254)
      echo "$ip is a router"
      ;;
    *)
      echo "$ip is not a router"
      ;;
  esac
done < /home/tux/Desktop/file

the below will produce all lines that do not end with 254

for i in [grep -v "254$" file]; do ping -c 1 $i done

slavik said: the below will produce all lines that do not end with 254

for i in [grep -v "254$" file]; do ping -c 1 $i done

that's wrong syntax

for i in `grep -v "254$"` file`
# for i in $(grep -v "254$" file)

sorry about the late reply but thanks for the help