[SOLVED] smallest number from biggest function.

Is it possible to do the following : [PHP]int biggestOfThree( int num1 , int num2 , int num3 ) {

int temp = (num1 > num2) ? num1 : num2; temp = ( temp > num3 ) ? temp : num3;

return temp; }

int smallestOfThree( int num1 , int num2 , int num3 ) {

// use biggestOfThree here to determine the smallest number. // do not use comparison stuff

return num3; } [/PHP]

Need to use biggestOfThree in smallestOfThree , to determine the smallest number without using comparison operators... I dont think its possible. what do u think?

StOoZ said:

what do u think?

Eye wood theenk

• It's perfectly pointless
• It can be done
• It takes more than one call to biggest

Easy:

smallesOfThree(a,b,c) { temp = biggestOfThree(-a,-b,-c); return -temp; }

StOoZ said: Is it possible to do the following :

[PHP]int biggestOfThree( int num1 , int num2 , int num3 ) {

int temp = (num1 > num2) ? num1 : num2; temp = ( temp > num3 ) ? temp : num3;

return temp; }

int smallestOfThree( int num1 , int num2 , int num3 ) {

// use biggestOfThree here to determine the smallest number. // do not use comparison stuff

return num3; } [/PHP]

Need to use biggestOfThree in smallestOfThree , to determine the smallest number without using comparison operators... I dont think its possible. what do u think? Why do you think it is impossible?

Reiger said: Easy:

smallesOfThree(a,b,c) { temp = biggestOfThree(-a,-b,-c); return -temp; }

I hadn't thought of that.

Even shorter:

return -biggestOfThree(-a,-b,-c);

thank you all!! ):P